SOLUTION: Find three consecutive even integers that the sum of the smallest and twice the second is 20 more than the third

Algebra.Com
Question 996569: Find three consecutive even integers that the sum of the smallest and twice the second is 20 more than the third
Answer by CubeyThePenguin(3113)   (Show Source): You can put this solution on YOUR website!
integers: (x-2), x, (x+2)

(x-2) + 2x = (x+2) + 20
3x - 2 = x + 22
2x = 24
x = 12

The integers are 10, 12, and 14.

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