SOLUTION: Find two whole numbers whose product is 147 and whose quotient is 3

Question 99515This question is from textbook
: Find two whole numbers whose product is 147 and whose quotient is 3 This question is from textbook

Answer by doukungfoo(195) (Show Source): You can put this solution on YOUR website!
Ok the object is to find two whole numbers. Lets call those numbers x and y.
Now the question states that these two numbers ( x and y) have a product that equals 147.
lets write that as and equation

We are also told that these numbers ( x and y ) have a quotient of 3
written as an equation we get this:

Ok lets take a look at the first equation:

We can set it in terms of x by dividing both sides by y like this:

Now we have x equal to 147 divided by y so if we take the second equation

and replace the x with 147/y we get this:

now we can solve for y
first multiply both sides by y

next multiply both sides by y again

now divide both sides by 3

finally solve for y by taking the square root of both sides

Now that we have found y equals 7 just replace the y in with 7
and solve for x

So now we have found two numbers 21 and 7
Their product is 147

and their quotient is 3