SOLUTION: The sum of the three times the greatest of four consecutive integers and nine is six more than twice the sum of the two smallest. What is the sum of all the integers?

SOLUTION: The sum of the three times the greatest of four consecutive integers and nine is six more than twice the sum of the two smallest. What is the sum of all the integers?

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Question 994938: The sum of the three times the greatest of four consecutive integers and nine is six more than twice the sum of the two smallest. What is the sum of all the integers?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
4 consecutive integers: x, (x+1), (x+2), (x+3)

3(x + 3) + 9 = 2(x + (x+1)) + 6
3x + 9 + 9 = 2(2x + 1) + 6
3x + 18 = 4x + 8
10 = x

sum of all integers = x + (x+1) + (x+2) + (x+3) = 10 + 11 + 12 + 13 = 46
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