SOLUTION: using n,n+2,and n+4 for three consecutive integers,express each statement as an equation,then find the integers. twenty times the sum of the second and the final and the third

SOLUTION: using n,n+2,and n+4 for three consecutive integers,express each statement as an equation,then find the integers. twenty times the sum of the second and the final and the third

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Question 994783: using n,n+2,and n+4 for three consecutive integers,express each statement as an equation,then find the integers.
twenty times the sum of the second and the final and the third equals 3 more thanthe first.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
20((n+2) + (n+4)) = 3 + n
20(2n + 6) = n + 3
40n + 120 = n + 3
39n = -117
n = -3
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