SOLUTION: The product of two consecutive positive integers is 56. What is the smaller integer?
Algebra.Com
Question 994756: The product of two consecutive positive integers is 56. What is the smaller integer?
Found 2 solutions by CubeyThePenguin, ikleyn:
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
Using some guessing and checking, we see that the integers are 7 and 8.
Here is a more algebraic approach:
smaller integer = x
x(x+1) = 56
x^2 + x = 56
x^2 + x - 56 = 0
(x + 8)(x - 7) = 0
x is positive, so x = 7.
Answer by ikleyn(52786) (Show Source): You can put this solution on YOUR website!
.
This problem/question is to check if you know the multiplication table . . .
RELATED QUESTIONS
The product of two consecutive positive integers is 12 more than 5 times the smaller... (answered by macston)
what is the smallest of 3 consecutive positive integers if the product of the
smaller... (answered by Edwin McCravy)
what is the smallest of 3 consecutive positive integers if the product of the smaller two (answered by CubeyThePenguin)
What is the smallest of 3 consecutive positive integers if the product of the smaller two (answered by CubeyThePenguin)
the product of two negative consecutive integers is 56. Find the... (answered by MathLover1)
The product of two consecutive even integers is 30 more than 9 times the smaller integer. (answered by josmiceli)
The product of two consecutive positive integers is 21 more than three times the larger... (answered by josgarithmetic)
the product of two positive consecutive integers is 56 , find the... (answered by stanbon)
find the smallest of three consecutive positive integers such that the product of two... (answered by ad_alta)