SOLUTION: Separate 132 into two parts such that if the larger is divided by the smaller. The quotient is 6 and the remainder is 13.

Question 994597: Separate 132 into two parts such that if the larger is divided by the smaller. The quotient is 6 and the remainder is 13.
Found 3 solutions by KMST, josgarithmetic, macston:
Answer by KMST(5328)   (Show Source): You can put this solution on YOUR website!
= the smaller part
= the larger part
If the larger part, , is divided by the smaller, , the quotient is 6 and the remainder is 13
means that , minus the remainder, divided by is exactly :

Solving:
-->-->-->-->-->--> .
Then -->
The two parts are and .
Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
This is just the description transcribed into algebraic symbolism.
.

Solve for x and y.
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
.
L=larger part; S=smaller part
.
S+L=132
L=132-S
.
L=6S+13
132-S=6S+13
119=7S
17=S
L=132-S=132-17=115
ANSWER: The two parts are 17 and 115.
.
CHECK:
L=6S+13
115=6(17)+13
115=102+13
115=115

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