SOLUTION: there are 3 consecutive even intergers, the first number is divided by 4. the second is divided by 5, the third is divided by8, the sum of the three quotients is 17 what is the mid

Question 992893: there are 3 consecutive even intergers, the first number is divided by 4. the second is divided by 5, the third is divided by8, the sum of the three quotients is 17 what is the middle interger?
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.
Let x be the middle of these three consecutive even integers.
Then the two others are (x-2) and (x+2).

The equation is

+ + = 17.

Simplify: multiply by 40 both sides.

10*(x-2) + 8*x + 5*(x+2) = 17*40 = 680.

10x - 20 + 8x + 5x + 10 = 680,

23x = 680 + 20 - 10 = 690.

x = = 30.

The numbers are 28, 30 and 32.

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