SOLUTION: ten times the larger if the two consecutive even integers minus seven times the smaller equals two times the sum of the two integers. find the integers

Question 992863: ten times the larger if the two consecutive even integers minus seven times the smaller equals two times the sum of the two integers. find the integers

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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S=smaller; L=larger=S+2
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10L-7S=2(L+S)
10(S+2)-7S=2(S+2+S)
10S+20-7S=4(2S+2)
3S+20=4S+4
16=S
ANSWER 1: The smaller integer is 16
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L=S+2=16+2=18
ANSWER 2: The larger integer is 18.
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CHECK:
10L-7S=2(L+S)
10(18)-7(16)=2(18+16)
180-112=2(34)
68=68
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