SOLUTION: Find three consecutive even integers such that their sum is eight less than twice the smallest.

Question 989661: Find three consecutive even integers such that their sum is eight less than twice the smallest.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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F=first integer; S=second integer=F+2; T=third integer=F+4
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F+S+T=2F-8
F+(F+2)+(F+4)=2F-8
3F+6=2F-8
F=-14 . ANSWER 1: The first integer is -14.
S=F+2=-14+2=-12 . ANSWER 2: The second integer is -12.
T=S+4=-14+4=-10 . ANSWER 3: The third integer is -10.
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CHECK:
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F+S+T=2F-8
(-14)+(-12)+(-10)=2(-14)-8
-36=-28-8
-36=-36
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