SOLUTION: You can represent an odd integer with the expression 2n+1, where n is any integer. Write and solve an equation to find three consecutive add integers that have a sum of 63.

Question 986585: You can represent an odd integer with the expression 2n+1, where n is any integer. Write and solve an equation to find three consecutive add integers that have a sum of 63.
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
You can represent an odd integer with the expression 2n+1, where n is any integer. Write and solve an equation to find three consecutive add integers that have a sum of 63.
=================
(n-2) + n + (n+2) = 63
3n = 63
n = 21
--> 19, 21, 23
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Let represent the smallest of the three consecutive odd integers. Since this odd integer is arbitrary, at least so far, we can say that it is the th odd integer, hence . The next consecutive odd integer must then be the th odd integer, or , which is to say . Since , must be . Similarly, the next consecutive odd integer is

Since the sum of these three odd integers is 63:

Solve for then compute and

John

My calculator said it, I believe it, that settles it

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