SOLUTION: The sum of the products of three consecutive integers taken twice at a time is 107. Find the integers.

SOLUTION: The sum of the products of three consecutive integers taken twice at a time is 107. Find the integers.

Algebra.Com

Question 981050: The sum of the products of three consecutive integers taken twice at a time is 107. Find the integers.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The sum of the products of three consecutive integers taken twice at a time is 107. Find the integers.
--------------
n-1, n, n+1 are the integers
n(n-1) + n(n+1) + (n-1)*(n+1) = 107
2n^2 + n^2 - 1 = 107
3n^2 = 108
n = 6
n = -6

RELATED QUESTIONS
Find three consecutive even integers such that the sum of the squares of the first and... (answered by josmiceli)

there are three consecutive integers. The sum of twice the second and third is 61. Find... (answered by mananth)

Find three consecutive integers such that twice the second subtracted from the sum of the (answered by nerdybill)

find three consecutive integers whose sum is 11 more than twice the greatest of the three (answered by ReadingBoosters)

The sum of three consecutive integers is at most 442 less twice the largest integer. What (answered by Theo)

three times the largest of three consecutive odd integers is three less than twice the... (answered by stanbon)

For two consecutive integers the sum of twice the larger in three times the smaller is... (answered by Edwin McCravy)

find four consecutive even integers where the sum of the first three is twice the... (answered by edjones)

Find three consecutive odd integers such that the sum of the first and third integers is... (answered by nvela)