SOLUTION: The least integer of a set of odd integers is -11. If the sum of these integers is 28, how
many integers are in the set?
The answer is 25, but how is it possible if the integer
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Question 979676: The least integer of a set of odd integers is -11. If the sum of these integers is 28, how
many integers are in the set?
The answer is 25, but how is it possible if the integers are from a consecutive set of ODD numbers(not including zero)? Should it be 14(-11,-9,-7,-5,-3,-1,1,3,5,7,9=0 and 13+15=18, hence 14)? Please help!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The least integer of a set of odd integers is -11. If the sum of these integers is 28, how
many integers are in the set?
The answer is 25, but how is it possible if the integers are from a consecutive set of ODD numbers(not including zero)? Should it be 14(-11,-9,-7,-5,-3,-1,1,3,5,7,9=0 and 13+15=18, hence 14)?
----------------
(-11,-9,-7,-5,-3,-1,1,3,5,7,9=0 **** = -2, not zero
----
13+15=18 **** = 28, not 18
-----------------------
(-11,-9,-7,-5,-3,-1,1,3,5,7,9,11) --> 0 with 12 elements.
13 + 15 = 28
--> 14 integers.
25 is not correct.
----------------
When adding odd integers, an even # of them --> an even sum.
An odd # of them --> an odd sum.
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