SOLUTION: The product of two consecutive integers is 12 less than the square of the lesser integer. Find the greater of the two integers.

Question 976996: The product of two consecutive integers is 12 less than the square of the lesser integer. Find the greater of the two integers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The product of two consecutive integers is 12 less than the square of the lesser integer. Find the greater of the two integers.
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x(x+1) = x^2-12
x^2 + x = x^2 - 12
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x = -12
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Ans: x+1 = -11
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Cheers,
Stan H.
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