SOLUTION: The width (w) of a rectangle is two less than 1/3 of its length (l). If the perimeter is 116 cm. identify the equation of the problem

Question 976555: The width (w) of a rectangle is two less than 1/3 of its length (l). If the perimeter is 116 cm. identify the equation of the problem
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Made more general,
The width (w) of a rectangle is k less than n/d of its length (L). If the perimeter is p cm. identify the equation of the problem.

Description means or .

Returning to the perimeter equation and substituting for w,

-----this may be one of your choices if keeping completely in symbolic form.

You can solve the equation for L, one of the unknown quantities.
-

That form for L might be fairly convenient to use. You can substitute as variables were assigned:
;
Evaluate L...
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

The width (w) of a rectangle is two less than 1/3 of its length (l). If the perimeter is 116 cm. identify the equation of the problem

Let length be L, and width, W
Then W =
2(L + W) = perimeter
2(L + W) = 116
2(L + W) = 2(58)
L + W = 58
------ Substituting for width
------ Required equation
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