SOLUTION: The sum of the two smaller of the three consecutive numbers exceeds the largest by 52. Find the numbers

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Question 972556: The sum of the two smaller of the three consecutive numbers exceeds the largest by 52. Find the numbers
Found 2 solutions by Boreal, lwsshak3:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
smallest=x
x+x+1-52=x+2
2x-51=x+2
x=53
the numbers are 53, 54, and 55
53+54 are 52 more than 55.

Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
The sum of the two smaller of the three consecutive numbers exceeds the largest by 52. Find the numbers.
***
let x=smallest of three consecutive numbers
x+1=next smallest of three consecutive numbers
x+2=largest of three consecutive numbers
..
x+(x+1)=x+2 (sum of the two smaller of the three consecutive numbers exceeds the largest by 52)
2x+1=x+2+52
x=53
smallest of three consecutive numbers=53
next smallest of three consecutive numbers=54
largest of three consecutive numbers=55

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