SOLUTION: the larger of two integers is 1 less than twice the smaller. if twice the square of the smaller is increased by the larger,the result is 39

Question 971235: the larger of two integers is 1 less than twice the smaller. if twice the square of the smaller is increased by the larger,the result is 39
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
smaller=x
larger is 2x-1
2x^2 + (2x-1) =39
2x^2+2x -1-39=0
2x^2+2x-40=0; divide out a 2.
x^2+x-20=0
(x+5)(x-4)=0
x= -5. 4
Try 4
Larger is 9
32+7=39 ;; yes
Try -5
Larger is -11
25*2 - 11=39
Two solutions work, 4, and -5

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

the larger of two integers is 1 less than twice the smaller. if twice the square of the smaller is increased by the larger,the result is 39

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