SOLUTION: what is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 11 more than 5 times the largest integer

Question 971109: what is the smallest of 3 consecutive positive integers if the product of the
smaller two integers is 11 more than 5 times the largest integer
Answer by Edwin McCravy(20055) (Show Source): You can put this solution on YOUR website!
what is the smallest of 3 consecutive positive integers if the product of the
smaller two integers is 11 more than 5 times the largest integer







Get 0 on the right side:



Factor the left side:



Set each factor = 0

n-7 = 0;  n+3 = 0
  n = 7;    n = -3

Since the problem specifically states "positive": 
we ignore the negative answer.

Answer: 7,8,9

Checking product of smaller two = 7*8 = 56

5 times the largest = 5*9 = 45

11 more than 45 is 56.

So the solution 7,8,9 is correct.
  
Edwin

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