SOLUTION: An integer is three more than another integer. Twice the larger integer is two less than the square of the smaller integer. Find the two integers

SOLUTION: An integer is three more than another integer. Twice the larger integer is two less than the square of the smaller integer. Find the two integers

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Question 969156: An integer is three more than another integer. Twice the larger integer is two less than the square of the smaller integer. Find the two integers
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
larger integer = x
smaller integer = y

x = y + 3
2x = y^2 - 2

Use substitution.

2(y + 3) = y^2 - 2
2y + 6 = y^2 - 2
0 = y^2 - 2y - 8
0 = (y - 4)(y + 2)

The integers are (x, y) = (7, 3) or (1, -2).
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