SOLUTION: What is a positive integer squared plus 9 times its consecutive integer is equal to 19?
Algebra.Com
Question 968569: What is a positive integer squared plus 9 times its consecutive integer is equal to 19?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x^2 + 9(x+1) = 19
x^2 + 9x + 9 = 19
x^2 + 9x - 10 = 0
(x + 10)(x - 1) = 0
x is positive, so x = 1.
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