SOLUTION: find 2 consecutive numbers such that one-seventh of the smallest
exceeds one-eight of the larger by 3.
Algebra.Com
Question 965459: find 2 consecutive numbers such that one-seventh of the smallest
exceeds one-eight of the larger by 3.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
n, and n+1.
Check how this equation conforms to the description:
RELATED QUESTIONS
two consecutive odd numbers are chosen so that one third of the smaller exceeds one... (answered by josmiceli)
Two consecutive odd integers are such that one third the smaller one is greater than... (answered by josgarithmetic,MathTherapy)
Find three consecutive multiples of seven such that the product of the largest two... (answered by ankor@dixie-net.com)
Find two positive consecutive even numbers such that four times the square of the smaller (answered by Fombitz)
Find two consecutive integers such that one-half of the larger exceeds one-third of the... (answered by ikleyn)
two consecutive odd integers are such, that one-third the smaller one is greater than... (answered by checkley79)
Find the consecutive numbers such that one- third the greater number exceeds one- fifth... (answered by reynard2007)
Two consecutive odd number are chosen so that one third of the smaller exceed one seventh (answered by math_helper)
1) Find two consecutive even numbers such that the difference of one-half of the larger... (answered by ankor@dixie-net.com)