SOLUTION: The product of two consecutive positive integers is 12 more than 5 times the smaller integer. Find the integers.
Algebra.Com
Question 965000: The product of two consecutive positive integers is 12 more than 5 times the smaller integer. Find the integers.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
x=smaller integer; x+1=larger integer
Subtract 5x from each side.
Subtract 12 from each side.
ANSWER 1: The smaller integer is 6.
= ANSWER 2: The larger integer is 7.
.
CHECK:
.
RELATED QUESTIONS
what is the smallest of 3 consecutive positive integers if the product of the
smaller... (answered by Edwin McCravy)
The product of two positive consecutive odd intgers is 5 more than 6 times the smaller... (answered by Alan3354)
The product of two consecutive positive intergers is 27 more than 5 times the larger... (answered by CubeyThePenguin)
The product of two consecutive positive integers is 27 more than five times the larger... (answered by TimothyLamb)
the product of two consecutive positive integers is 52 more than 8 times the larger... (answered by hkwu)
The product of two consecutive positive integers is 22 more than eight times the larger... (answered by amarjeeth123)
The product of two positive consecutive integers is 24 more than nine times the larger... (answered by CubeyThePenguin)
The product of two consecutive positive integers is 27 more than five times the larger... (answered by CubeyThePenguin)
The product of two consecutive positive integers is 12 more than 12 times the dum of... (answered by Alan3354)