SOLUTION: find three consecutive even integers such that the product of the first and second is equal to two less than five times the third number

SOLUTION: find three consecutive even integers such that the product of the first and second is equal to two less than five times the third number

Algebra.Com

Question 963075: find three consecutive even integers such that the product of the first and second is equal to two less than five times the third number
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

(x-2)(x) = 5(x+2) - 2
x^2 - 2x = 5x + 8
x^2 - 7x - 8 = 0
(x - 8)(x + 1) = 0

x is even, so x = 8.

The integers are 6, 8, and 10.
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