SOLUTION: Find the four consecutive integers such that six times the sum of the first and third is 12 greater than 9 times the fourth.

Question 962816: Find the four consecutive integers such that six times the sum of the first and third is 12 greater than 9 times the fourth.
Found 2 solutions by 0saidong9, MathTherapy:
Answer by 0saidong9(5) (Show Source): You can put this solution on YOUR website!
Let x = 1st number
let x + 1 = 2nd number
let x + 2 = 3rd number
let x + 4 = 4th number

6(x+x+2)-12 > 9(x+3)
6(2x+2) - 12 > 9x+ 27
12x + 12 - 12 > 9x + 27
3x > 27
x > 9
____________________
first number : x > 9
2nd : x > 10
3rd : x > 11
4th : x > 12

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Find the four consecutive integers such that six times the sum of the first and third is 12 greater than 9 times the fourth.

Numbers:
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