SOLUTION: Find four consecutive positive integers such that the product of the first two is greater than the product of 3 and the fourth.
Algebra.Com
Question 961459: Find four consecutive positive integers such that the product of the first two is greater than the product of 3 and the fourth.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive positive integers: x, (x+1), (x+2), (x+3)
(x)(x+1) > (x+2)(x+3)
x^2 + x > x^2 + 5x + 6
x > 5x + 6
0 > 4x + 6
4x + 6 < 0
4x < 6
x < 6/4 = 1.5
x has to be 1.
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