SOLUTION: Given two numbers such that the difference of the first and the second numbers is 11. If the sum of twice the first number and the second number is 12, find the numbers. solution.

Question 960855: Given two numbers such that the difference of the first and the second numbers is 11. If the sum of twice the first number and the second number is 12, find the numbers.
solution. :
x - y=11 , where x= 1st no. , y= 2nd no

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!

x=first number; y=second number
x-y=11
x=11+y
2x+y=12 Substitute for x
2(11+y)+y=12
22+2y+y=12 Subtract 22 from each side.
3y=-10 Divide each side by 3
y=-10/3 ANSWER 1: The second number is -10/3.
x=11+y=11-10/3=23/3 ANSWER 2: The first number is 23/3.
CHECK:
23/3-(-10/3)=11
33/3=11
11=11
2x+y=12
2(23/3)+(-10/3)=12
46/3-10/3=12
36/3=12
12=12
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