SOLUTION: Find three consecutive positive integers such that the cube of the smallest minus the square of the largest is 5 more than 3 times the second integer

SOLUTION: Find three consecutive positive integers such that the cube of the smallest minus the square of the largest is 5 more than 3 times the second integer

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Question 959895: Find three consecutive positive integers such that the cube of the smallest minus the square of the largest is 5 more than 3 times the second integer
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive positive integers: (x-1), x, (x+1)

(x-1)^3 - 5(x+1)^2 = 5 + 3x
x^3 - 3x^2 + 3x - 1 - (5x^2 + 10x + 5) = 3x + 5
x^3 - 8x^2 - 7x - 6 = 3x + 5
x^3 - 8x^2 - 10x - 11 = 0

This equation has no integer solutions.
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