SOLUTION: The product of two consecutive intergers is 16 more than 8 times the smaller integer. Determine the integers.

Question 959778: The product of two consecutive intergers is 16 more than 8 times the smaller integer. Determine the integers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The product of two consecutive integers is 16 more than 8 times the smaller integer. Determine the integers.
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1st: x
2nd: x+1
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Equation:
x(x+1) = 8x + 16
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x^2 + x = 8x + 16
x^2 - 7x - 16 = 0
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x = [7 +- sqrt(49-4*-16))]/2
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x = [7 +- sqrt(113)]/2
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This does not produce integer solutions.
Cheers,
Stan H.
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