SOLUTION: Find three consecutive integers such that the product of the two largest is 20 more than the smallest integer

SOLUTION: Find three consecutive integers such that the product of the two largest is 20 more than the smallest integer

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Question 954750: Find three consecutive integers such that the product of the two largest is 20 more than the smallest integer
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

x(x+1) = 20 + x - 1
x^2 + x = 20 + x - 1
x^2 = 19

This equation has no integer solutions.
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