SOLUTION: Find two consecutive integers such that the smaller integer is six more than twice the larger integer.
Algebra.Com
Question 954313: Find two consecutive integers such that the smaller integer is six more than twice the larger integer.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: x, (x+1)
x = 6 + 2(x+1)
x = 6 + 2x + 2
x = 2x + 8
-x = 8
x = -8
The integers are -8 and -7.
RELATED QUESTIONS
find two consecutive even integers such that four times the smaller integer is six more... (answered by CubeyThePenguin)
Find two consecutive even integers such that the sum of the smaller integer plus twice... (answered by Alan3354)
Find two positive even consecutive integers such that one less than the square of the... (answered by mananth)
find two consecutive even integers such that six times the smaller integer equals five... (answered by math_helper)
find two consecutive even integers such that five times the smaller integer is ten more... (answered by hamsanash1981@gmail.com)
find two consecutive even integers such that five times the smaller integer is ten more... (answered by CubeyThePenguin)
two consecutive even integers such that the sum of twice the smaller integer plus the... (answered by ewatrrr)
find two consecutive positive integers such that the square of the smaller integer added (answered by oscargut)
Find two consecutive integers such that twice the smaller is two more than the... (answered by CubeyThePenguin)