SOLUTION: The product of two consecutive integers is the square of the lesser integer minus 11. Find the greater of the two integers.

Question 953991: The product of two consecutive integers is the square of the lesser integer minus 11. Find the greater of the two integers.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The product of two consecutive integers is the square of the lesser integer minus 11.
Find the greater of the two integers.
:
Two integers n, (n+1)
n(n+1) = n^2 - 11
n^2 + n = n^2 - 11
subtract n^2 fro both sides
n = -11
then
-11 + 1 = -10 is the greater integer
:
see if that works
-11(-11 + 1) = (-11)^2 - 11
-11(-10) = 121 - 11
+110 = +110
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