SOLUTION: Find three consecutive positive odd intergers such that the sum of the squares of the first two integers is 15 less than the square of the third

Question 950544: Find three consecutive positive odd intergers such that the sum of the squares of the first two integers is 15 less than the square of the third
Answer by jhaashok630(18) (Show Source): You can put this solution on YOUR website!
three consecutive positive odd intergers such that the sum of the squares of the first two integers is 15 less than the square of the third
let x= first odd integer
2nd integer = x+2
3rd integer = x+4
x^2+(x+2)^2=(x+4)^2-15
x=1 , 3 , 5
RELATED QUESTIONS
Find three consecutive odd integers such that the sum of the squares of the first two is (answered by CubeyThePenguin)

the sum of the squares of two consecutive odd positive intergers is 202. find the... (answered by solver91311,Alan3354)

find three consecutive odd positive intergers such that 2 times the sum of all three is... (answered by solver91311)

Find three consecutive positive odd integers such that the sum of their squares is... (answered by ramkikk66,mananth,Alan3354)

Find three consecutive odd intergers such that twice the sum of the smaller two integers... (answered by math_tutor2020,josgarithmetic,ikleyn)

find three consecutive odd positive integers such that 2 times the sum of all three is... (answered by ankor@dixie-net.com)

find three consecutive intergers such that the sum of the first two integers is 24 more... (answered by josmiceli)

Find three consecutive odd integers such that the sum of the last two is 15 less than... (answered by mananth)

Find three consecutive odd positive integers such that two times the sum of all three is... (answered by edjones)