SOLUTION: An interger is four less than twice another. If the product of the two intergers is 70, one pair of intergers that will satisfy the problem is____.

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Question 950347: An interger is four less than twice another. If the product of the two intergers is 70, one pair of intergers that will satisfy the problem is____.
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
F=first integer; S= second integer
FS=70
S=70/F
F-4=2S Substitute for S
F-4=2(70/F)
F-4=140/F Multiply each side by F.
F^2-4F=140 Subtract 140 from each side.
F^2-4F-140=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=576 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 14, -10. Here's your graph:

Answers F=14 and F=-10
S=70/F=70/14=5 ANSWER 1: One pair of integers that satisfies the problem is 14 and 5.
For F=-10
S=70/F=70/-10=-7 ANSWER 2: Another pair of numbers that satisfies the problem is -10 and -7.
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