SOLUTION: find three consecutive even integers such that 3 times the sum of the last two even integers is 40 more than 5 times the first integer

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Question 947854: find three consecutive even integers such that 3 times the sum of the last two even integers is 40 more than 5 times the first integer

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
2n, 2n+2, 2n+4.


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

find three consecutive even integers such that 3 times the sum of the last two even integers is 40 more than 5 times the first integer
Let the smallest integer be S
Then others are: S + 2, and S + 4
We then have: 3(S + 2 + S + 4) = 5S + 40
3(2S + 6) = 5S + 40
Solve for S, the smallest integer
Add 2 to S, or the smallest integer to get the middle larger
Add 2 to the middle integer or 4 to the smallest integer to get the 3rd or largest integer
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