SOLUTION: the square root of th sum of two consecutive odd integers is 6√2. Find the larger integer.

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Question 945304: the square root of th sum of two consecutive odd integers is 6√2. Find the larger integer.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!
2n+1 and 2n+3 are the two integers.









What do you guess comes next?




--
The integers are 35 and 37.

Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

the square root of th sum of two consecutive odd integers is 6√2. Find the larger integer.
Let larger integer be L
Then smaller is: L - 2
We then have:

------- Squaring both sides
2L - 2 = 36(2)
2L - 2 = 72
2L = 72 + 2
2L = 74
L, or larger integer = , or
You can do the check!!
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