SOLUTION: Find two consecutive odd integers such that when the smaller is doubled, the results is 7 more than the larger integer.

Question 944490: Find two consecutive odd integers such that when the smaller is doubled, the results is 7 more than the larger integer.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
S=smaller integer; L=larger integer=S+2
2S=L+7 Substitute for L
2S=(S+2)+7
2S=S+9 Subtract S from each side
S=9 ANSWER 1 Smaller Number is 9
L=S+2=9+2=11 ANSWER 2 Larger number is 11
CHECK:
Double the smaller is 7 more than the larger.
2S=L+7
2(9)=(11)+7
18=18

RELATED QUESTIONS
Find two consecutive odd integers such that twice the larger is 17 more than the... (answered by QH)

Find two consecutive odd integers such that twice the larger is 17 more than the... (answered by mananth)

If the smaller of two consecutive odd integers is doubled, the result is 7 more than the... (answered by stanbon)

Find three consecutive odd integers such that the sum of the first two smaller integers... (answered by josgarithmetic)

find three consecutive odd integers such that the sum of the first two smaller integers... (answered by rothauserc)

Find two consecutive integers such that the smaller integer is six more than twice the... (answered by CubeyThePenguin)

Find two consecutive odd integers such that for times the larger is 29 more than three... (answered by sarah_adam)

Find two consecutive odd integers such that 4 times the larger is 29 more than 3 times... (answered by Alan3354)

find two consecutive odd integers such that 4 times the larger is 29 more than 3 times... (answered by ewatrrr)