SOLUTION: find three consecutive integers such that the sum of the first and three times the second is eighteen less than five times the third integer.

Question 942798: find three consecutive integers such that the sum of the first and three times the second is eighteen less than five times the third integer.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
Three consecutive integers:I, I+1, I+2
Sum of first and three times second: I+(3(I+1))
is 18 less than 5 times the third 5(I+2)-18
I+3I+3=5I+10-18
4I+3=5I-8 add 8 to each side
4I+3+8=5I-8+8
4I+11=5I subtract 4I from each side
4I+11-4I=5I-4I
11=I The first integer is 11
I+1=12 The second integer is 12
I+2=13 The third integer is 13
CHECK
11+3(12)=5(13)-18
11+36=65-18
47=47
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