SOLUTION: The product of two consecutive integers is 2less than the square of the lesser integer. Find the greater of the two integers. The greater of the two integers is?

Question 937790: The product of two consecutive integers is 2less than the square of the lesser integer. Find the greater of the two integers.
The greater of the two integers is?

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The two consecutive integers: x, (x+1)
:
The product of two consecutive integers is 2less than the square of the lesser integer.
x(x+1) = x^2 - 2
x^2 + x = x^2 - 2
x^2 - x^2 + x = -2
x = -2
Find the greater of the two integers.
-2 + 1 = -1, is the greater

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