SOLUTION: find three consecutive positive odd integers such that the sum of the squares of the first and second integers is equal to the square of the third integer minus 7.

Question 937242: find three consecutive positive odd integers such that the sum of the squares of the first and second integers is equal to the square of the third integer minus 7.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

(x-2)^2 + x^2 = (x+2)^2 - 7
(x^2 - 4x + 4) + x^2 = (x^2 + 4x + 4) - 7
2x^2 - 4x + 4 = x^2 + 4x - 3
x^2 - 8x + 7 = 0
(x - 1)(x - 7) = 0

The integers have to be positive, so x = 7 and the integers are {5, 7, 9.}
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