SOLUTION: Find 3 consecutive even integers such that 3 times the first equal to the sum of the other 2 consecutive even integers.

Question 937175: Find 3 consecutive even integers such that 3 times the first equal to the sum of the other 2 consecutive even integers.
Found 2 solutions by ewatrrr, srinivas.g:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
3 consecutives even integers: x, x+2,x+4
3x = 2x+6
x = 6
.....
3 consecutives even integers: 6, 8, 10
and... checking
18 = 18
Answer by srinivas.g(540) (Show Source): You can put this solution on YOUR website!
let 3 consecutive even integers be x,x+2,x+4
3 times the first equal to the sum of the other 2 consecutive even integers
3*x= x+2+x+4
3x= 2x+6
3x-2x= 6
x=6
x+2 = 6+2 = 8
x+4 = 6+4 = 10
3 consecutive integers (x,x+2. x+4) are 6,8,10
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