SOLUTION: the sum of three consecutive integers is 26 more than the smallest integer
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Question 933235: the sum of three consecutive integers is 26 more than the smallest integer
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
the sum of three consecutive integers is 26 more than the smallest integer
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1st:: x-1
2nd:: x
3rd:: x+1
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Sum = 3x = (x-1)+26
3x = x+25
2x = 25
x = 12.5
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Not an integer.
No solution.
Cheers,
Stan H.
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Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
by definition: Integers are like whole numbers, but they also include negative numbers, but still no fractions allowed!
let the first integer be , the second is and the third is
the smallest integer is
if the sum of three consecutive integers is more than the smallest integer, then we have:
...solve for
it is not an integer which is a number with fractional part
let’s try with
three consecutive even integers ---> ,, and
your integers are: ,, and
try also three consecutive odd integers are of the form:
....it is an integer either
so, you must have three consecutive integers to have a solution
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