SOLUTION: The product of two consecutive even integers is 56 less than 8 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers fir

Question 926959: The product of two consecutive even integers is 56 less than 8 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.
I get that the first number would be x, and the second would be x+2; so the first portion of the equation would be x(x+2). It is the second part, 56 less than 8 times their sum. HELP!
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Write as We Read
x(x+2) = 8(x + x+2) - 56
x^2 + 2x = 16x + 16 - 56
x^2 -14x + 40 = 0
(x - 4)(x - 10) = 0
x = 4, 10
the two consecutive even integers are: (4, 6) and (10, 12)
.....
and..checking
24 = 8(10) - 56 = 24
120 = 8( 22) - 56 = 120
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