SOLUTION: The sum of the digits of a two-digit number is 6. The number with the digits in reverse order is 6 less than twice the original number. Find the original number.

Question 921686: The sum of the digits of a two-digit number is 6. The number with the digits in reverse order is 6 less than twice the original number. Find the original number.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
number: AB

A + B = 6
10B + A = 2(10A + B) - 6

Substitute B = 6 - A into the second equation.

10(6 - A) + A = 2(10A + 6 - A) - 6
60 - 10A + A = 18A + 12 - 6
60 - 9A = 18A + 6
54 = 27A
A = 2 ---> B = 4

The original number is AB = 24.
RELATED QUESTIONS
/./The sum of the digits of a two-digit number is 6. The number with the digits in... (answered by venugopalramana)

Five times the sum of the digits of a two-digit number is 13 less than the original... (answered by amarjeeth123)

Five times the sum of the digits of a two-digit number is 13 less than the original... (answered by josmiceli)

Five times the sum of the digits of a two-digit number is 13 less than the original... (answered by lwsshak3)

Five times the sum of the digits of a two-digit number is 13 less than the original... (answered by MathTherapy)

this is actually a digit problem. 1. the units digit of a two digit number is 6. The... (answered by richard1234)

Please help me solve this, all help is appreciated!! Five times the sum of the digits... (answered by ewatrrr)

If 45 is added to a two-digit number, the result is a number with the same digits, but in (answered by richard1234)

Five times the sum of the digits of a two-digit number is 13 less than the original... (answered by stanbon)