SOLUTION: find three consecutive odd integers such that the sum of the first and the second is 201 less the square of the third

SOLUTION: find three consecutive odd integers such that the sum of the first and the second is 201 less the square of the third

Algebra.Com

Question 920030: find three consecutive odd integers such that the sum of the first and the second is 201 less the square of the third
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

(x-2) + x = (x+2)^2 - 201
2x - 2 = x^2 + 4x - 197
0 = x^2 + 2x - 195
0 = (x + 15)(x - 13)

The integers could be {-17, -15, -13} or {11, 13, 15}.
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