SOLUTION: The product of two consecutive even integers is 40 less than 8 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first
Algebra.Com
Question 917892: The product of two consecutive even integers is 40 less than 8 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive even integers: x, (x+2)
x(x+2) = 8(x + (x+2)) - 40
x^2 + 2x = 8(2x+2) - 40
x^2 + 2x = 16x - 24
x^2 - 14x + 24 = 0
(x - 2)(x - 12) = 0
The integers could be 2 and 4 or 12 and 14.
RELATED QUESTIONS
The product of two consecutive even integers is 30 less than 15 times their sum. Find the (answered by ankor@dixie-net.com)
The product of two consecutive even integers is 18 less than 9 times their sum. Find the... (answered by dfrazzetto)
The product of two consecutive even integers is 76 less than 10 times their sum. Find the (answered by CubeyThePenguin)
The product of two consecutive even integers is 10 less than five times their sum. Find... (answered by stanbon)
the sum of two consecutive even integers is 34 less than their product. find the... (answered by ewatrrr)
The product of two consecutive odd integers is 49 less than 8 times their sum. Find the... (answered by stanbon,MathTherapy)
The product of two consecutive even integers x and y is 40 less than 20 times their sum.... (answered by ewatrrr)
The product of two consecutive even integers is 12 less than 6 times their... (answered by mananth)
The product of two consecutive even integers is 12 less than 6 times their... (answered by TimothyLamb)