SOLUTION: find three consecutive integer such that twice the greater integer is 2 less than 3 times the least integer

SOLUTION: find three consecutive integer such that twice the greater integer is 2 less than 3 times the least integer

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Question 916876: find three consecutive integer such that twice the greater integer is 2 less than 3 times the least integer
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integer: (x-1), x, (x+1)

2(x+1) = 3(x-1) - 2
2x+2 = 3x-5
7 = x

The integers are 6, 7, and 8.
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