SOLUTION: the product of two consecutive positive even integers is 10 more than 11 times the smaller of the integers. find the integers

Question 916698: the product of two consecutive positive even integers is 10 more than 11 times the smaller of the integers. find the integers
Answer by dkppathak(439) (Show Source): You can put this solution on YOUR website!
the product of two consecutive positive even integers is 10 more than 11 times the smaller of the integers. find the integers
let number is X and other number is X+2
X(x+2)= 10+11x
X^2+2x-10-11x=0
x^2-9x-10=0
X^2-10x+x-10=0
x(x-10)-1(x-10)=0
(x-10) (x-1)=0
x=10 or X=1
10 only even number where as 1 is odd number therefor 10 is right answer
so consecutive even numbers are 10 and 12
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