SOLUTION: The sum of eight consecutive odd numbers is 192.Find the last number of the sequence.

Question 914256: The sum of eight consecutive odd numbers is 192.Find the last number of the sequence.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Hint:

First Number: x
Second Number: x+2
Third Number: x+4
Fourth Number: x+6
Fifth Number: x+8
Sixth Number: x+10
Seventh Number: x+12
Eighth Number: x+14

Add up all the numbers and then set that sum equal to 192

x+(x+2)+(x+4)+(x+6)+(x+8)+(x+10)+(x+12)+(x+14) = 192

Solve for x. I'll let you do this part. Once you have the value of x, use it to find the value of x+14.
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