SOLUTION: find 3 consecutive even integers such that the sum of 1st and 3rd is 192.

Algebra.Com
Question 913473: find 3 consecutive even integers such that the sum of 1st and 3rd is 192.
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
x = first integer
x+2 = second consecutive even integer
x+4 = third consecutive even integer

"the sum of 1st and 3rd is 192." ---->
















The first integer is .

The second integer is

The third integer is

=======================================================

Final Answer: The three integers are 94, 96, 98


Let me know if you need more help or if you need me to explain a step in more detail.
Feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html

Thanks,

Jim

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