SOLUTION: find three consecutive positive odd integers such that the sum of the squares of the first and second integers is equal to the square of the third integer minus 7

Question 911418: find three consecutive positive odd integers such that the sum of the squares of the first and second integers is equal to the square of the third integer minus 7
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find three consecutive positive odd integers such that the sum of the squares of the first and second integers is equal to the square of the third integer minus 7
***
let x=1st consecutive odd integer
let x+2=2nd consecutive odd integer
let x+4=3rd consecutive odd integer
..
x^2+(x+2)^2=(x+4)^2-7
x^2+x^2+4x+4=x^2+8x+16-7
x^2-4x-5=0
(x-5)(x+1)=0
x=5
x+2=7
x+4=9
three consecutive positive odd integers are: 5, 7, 9
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