SOLUTION: Find three consecutive integers such that the product of the first and the third integers exceeds 4 times the second by 20.

SOLUTION: Find three consecutive integers such that the product of the first and the third integers exceeds 4 times the second by 20.

Algebra.Com

Question 904766: Find three consecutive integers such that the product of the first and the third integers exceeds 4 times the second by 20.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

(x-1)(x+1) = 4x + 20
x^2 - 1 = 4x + 20
x^2 - 4x - 21 = 0
(x + 3)(x - 7) = 0

The integers could be {-4, -3, -2} or {6, 7, 8}.
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